The point (2, l) is shifted by $3\sqrt{2}$ units parallel $x+y=1$  the line in the direction of increasing ordinate, to reach Q The image of C2 in the line $x+y=1$, is

detailed solution

Correct option is B

The equation of a line passing through (2, 1) and parallel to x + y = 1 isx−2cos⁡3π/4=y−1sin⁡π/4 or ,x−1−1/2=y−11/2The coordinates of points on this line which are at a distance 32 from (2, 1) are given byx−2−1/2=y−11/2=±32⇒x=2+3, y=1±3But, the ordinate of Q is more than that of P ( 2, 1 ). So, the coordinates of Q are (- 1, 4). The image of Q (- 1, 4) in the line x + y = 1 is given byx+11=y−41=−2−1+4−112+12x+11=y−41=−2⇒x=−3,y=2Thus, the coordinates of the required point are (- 3, 2)