Download the app

Questions  

The air tight and smooth pistons of a cylindrical vessel are connected with a string, as shown. Initially, pressure and temperature of the gas are P0 and T0. The atmospheric pressure is also P0. At a later time. tension in the string is 38P0A where A is the crosssectional are of the cylinder. At this time, the temperature of the gas has become:

a
38T0
b
34T0
c
118T0
d
138T0

detailed solution

Correct option is C

T+P0A=PA             T=P−P0A=38P0A (given) P=38P0+P0=118P0Now volume is constant by stringSo, P ∝ TInitial temperature is T0.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

For one-mole ideal gas, a process follows the relation P=V2V2+V02P0, where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?


phone icon
whats app icon