Q.

For one-mole ideal gas, a process follows the relation P=V2V2+V02P0, where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?

Moderate

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−2P0V05R

11P0V010R

−5P0V04R

P0V0

answer is 2.

(Detailed Solution Below)

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Detailed Solution

PV = nRTwhere n = number of moles and R = gas constantBy putting the value of volume V = V0 in the equation given in the problem, for ideal gas we get,P=P02;RT1=P02V0…(1)and with volume V = 2V0 the given equation provides the pressure value,P=4P05RT2=4P052V0…(2)Subtracting equation (1) from (2)∴T2−T1=11P0V010R

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