Questions
The average collision period in a gas undergoing isobaric process is
detailed solution
Correct option is C
Average collision period, t=1πd2vn2⇒t∝1vn (v = average speed, n = number density of molecules).v=8RTπMαT and n=NVα1VIn isobaric process, Vα TSo, tα1vnαVTαTTalk to our academic expert!
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Calculate the ratio of the mean free paths of the molecules of two gases having molecular diameters 1 and 2 . The gases may be considered under identical conditions of temperature, pressure and volume.
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