First slide

laws

Question

In Boyle's experiment for a given gas at different temperatures, the graph drawn between pressure and density are straight lines as shown, then

Moderate

A

T₁ > T₂
B

T₂ > T₁
C

T₁ = T₂
D

T₁³ = T₂

Solution

We know, PV = nRT
$\Rightarrow PV = \left( {nM} \right)\frac{{RT}}{M} = m\frac{{RT}}{M}$
where M = molar mass and m = Mass of gas.
$\therefore P = \left( {\frac{m}{V}} \right)\frac{{RT}}{M} = d\left( {\frac{{RT}}{M}} \right)$
where RT/M = Slope of P-V graph.
$\therefore \frac{{R{T_2}}}{M} < \frac{{R{T_1}}}{M}$
$\Rightarrow {T_1} > {T_2}$

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