First slide

Change in internal energy

Question

A closed container contains 2 moles of $H_{2} .$ If one mole of $H_{2}$ is dissociated into atomic hydrogen, then molar specific heat of the mixture at constant volume is

Moderate

A

$\frac{11 R}{6}$
B

$\frac{7 R}{2}$
C

$\frac{7 R}{6}$
D

$\frac{8 R}{3}$

Solution

(1)
After dissociation, the container contains a mixture of 2 mole of mono atomic gas and 1 mole of diatomic gas
$∴ C_{V} = \frac{n_{1} C_{V 1} + n_{2} C_{V 2}}{n_{1} + n_{2}} = \frac{2 \times \frac{3 R}{2} + 1 \times \frac{5 R}{2}}{2 + 1} = \frac{11 R}{6} .$

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