100 mol of an ideal gas is heated from 10° to 20°C keeping its (i) volume constant (ii) pressure constant.Let ΔUa and ΔUb denote the change in the internal energy of the gas due to process (i) and (ii),respectively. Then, which of the following shall be true?
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
ΔUa = ΔUb
b
ΔUa > ΔUb
c
ΔUa < ΔUb
d
ΔUa = ΔUb = 0
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
(i) Volume is constant, i.e. ΔV=0⇒ ΔUa=Q−pΔV⇒ ΔUa=Q(ii) Pressure is constant, i.e. Δp=0⇒ ΔUb=Q−pΔV∴ ΔUa>ΔUb