Determine the separation of the first line of the Balmer series (in Å) in a spectrum of ordinary hydrogen and tritium (mass number 3). Take Rydberg's constants = 10967800 m-1.
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answer is 2.387.
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Detailed Solution
First line of Balmer series of H-atom is1λH=R14−19×mHme+mHFirst line of Balmer series for Z-atom is1λT=R14−19×mTme+mH⇒λH−λT=36me+mH5RmH−36me+mT5RmT=365Rme+mHmT−me+mTmHmHmT=365RmemT−mHmHmT=365×10967800×9.109×10−31×2×1.67×10−273×1.67×10−27=2.387Å