If the series limit of Lymen series for Hydrogen atom is equal to the series limit of Balmer series for a hydrogen like atom, then what is the atomic number of this hydrogen like atom?
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answer is 2.
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Detailed Solution
By using 1λ=RZ21n12−1n22 For hydrogen atom 1λminH=R112−1∞=R⇒ λminH=1R For hydrogen like atom 1λminatom =RZ2122−1∞⇒ λminatom=4RZ2 From Eqs. (i) and (ii) 1R=4RZ2⇒Z=2 .
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If the series limit of Lymen series for Hydrogen atom is equal to the series limit of Balmer series for a hydrogen like atom, then what is the atomic number of this hydrogen like atom?