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Q.

A double charged lithium atom is equivalent to hydrogen whose atomic number is 3. The wavelength of required radiation for emitting electron from first to third Bohr orbit in  Li++ will be (Ionization energy of hydrogen atom is 13.6 eV)

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a

182.51Å

b

177.17Å

c

142.25Å

d

113.74Å

answer is D.

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Detailed Solution

En=−13.6Z2n2eV Required energy for said transition,ΔE=E3−E1=13.6Z2112−132 ⇒ΔE=13.6×3289=108.8eV ΔE=108.8×1.6×10−19J  Now ΔE=hcλ=108.8×1.6×10−19 ⇒λ=6.6×10−34×3×108108.8×1.6×10−19 =0.11374×10−7m=113.74Å
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