A double charged lithium atom is equivalent to hydrogen whose atomic number is $$3$$. The wavelength of required radiation for emitting electron from first to third Bohr orbit in $$Li++$$ will be (Ionization$$ energy of hydrogen atom is $$13.6$$ $$eV)

Question

A double charged lithium atom is equivalent to hydrogen whose atomic number is $$3$$. The wavelength of required radiation for emitting electron from first to third Bohr orbit in  $$Li++$$ will be (Ionization$$ energy of hydrogen atom is $$13.6$$ $$eV)

Infinity Learn · Accepted Answer

$$En=$$−$$13.6Z2n2eV$$ Required energy for said transition,Δ$$E=E3$$−$$E1=13.6Z2112$$−$$132$$ ⇒Δ$$E=13.6$$×$$3289=108.8eV$$ Δ$$E=108.8$$×$$1.6$$×$$10$$−$$19J$$  Now Δ$$E=hc$$λ$$=108.8$$×$$1.6$$×$$10$$−$$19$$ ⇒λ$$=6.6$$×$$10$$−$$34$$×$$3$$×$$108108.8$$×$$1.6$$×$$10$$−$$19$$ $$=0.11374$$×$$10$$−$$7m=113.74$$Å

A double charged lithium atom is equivalent to hydrogen whose atomic number is 3. The wavelength of required radiation for emitting electron from first to third Bohr orbit in $L i^{+ +}$ will be (Ionization energy of hydrogen atom is 13.6 eV)

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A double charged lithium atom is equivalent to hydrogen whose atomic number is 3. The wavelength of required radiation for emitting electron from first to third Bohr orbit in Li++ will be (Ionization energy of hydrogen atom is 13.6 eV)

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A double charged lithium atom is equivalent to hydrogen whose atomic number is 3. The wavelength of required radiation for emitting electron from first to third Bohr orbit in $L i^{+ +}$ will be (Ionization energy of hydrogen atom is 13.6 eV)