Heat engine
Question
The efficiency of a carnot engine is 50%. The temperature of the hot reservoir is kept constant. By what amount should the temperature of the cold reservoir be decreased so that efficiency becomes 60%.
Moderate
Solution
0.5 = 1 – TC/TH.
And 0.6 = 1 – (TC + x)/TH.
From the first equation we get: 5/10 = TC/TH.
From the second equation we get: 4/10 = (TC + x)/TH.
Now, we see that the value of x must be 1K.
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