The electric resistance of a certain wire of iron is R. If its length and radius are both doubled, then
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a
the resistance will be doubled and the specific resistance will be halved
b
the resistance will be halved and the specific resistance will remain unchanged
c
the resistance will be halved and the specific resistance will be doubled
d
the resistance and the specific resistance, will both remain unchanged
answer is B.
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Detailed Solution
The formula for resistance of wire isR=ρlAwhere ρ = specific resistance of the wire⇒R∝lA⇒R∝1r2 ∵ A=πr2∴ R1R2= l1l2 × r22r12 ....iGiven, l1 =l, l2 =2l, r1=r, r2=2r, R1=RSubstituting these values in Eq. (i), we haveR1R2= l2l × 2r2r 2R1R2=2 and R2 =R2Therefore, resistance will be halved.Now the specific resistance of the wire does not depend on the geometry of the wire, hence, it remains unchanged.Aliter: R ∝ lr2 ⇒ R1R2 = l2 l1 × r12r22 = 21 × 212=12⇒ R2 = R12, specific resistance doesn't depend upon length and radius.