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Q.

An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengths and radii of the wires are in the ratio of (4/3) and (2/3), then the ratio of the currents passing through the wires will be

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a

3

b

1/3

c

8/9

d

2

answer is B.

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Detailed Solution

See. figFrom figure VA−VB=i1R1=i2R2∴ i1i2=R2R1……………..(1)We know that R=ρl/πr2 or R∝l/r2So, R2R1=l2l1×r12r22Given that l1l2=43 and r1r2=23∴ R2R1=34×232=13………………(2)From eqs. (1) 8nd (2), we geti1i2=13

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