First slide

Graphs

Question

Figure below shows two paths that may be taken by a gas to go from a state A to a state C :

In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be :

Moderate

A

500 J
B

460 J
C

300 J
D

380 J

Solution

In cyclic process ABCA,
$∆ U_{cyclic} = 0 Q_{cyclic} = W_{cyclic} Q_{AB} + Q_{BC} + Q_{CA} = closed loop area 400 + 100 + Q_{CA} = \frac{1}{2} \times (2 \times 10^{- 3}) \times 4 \times 10^{4} 400 + 100 - Q_{AC} = 40 Q_{AC} = 460 J$

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