A thermodynamic system is taken through the cycle ABCD. as shown in figure. Total heat rejected by the gas during the cycle is
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a
2PV
b
4PV
c
1/2PV
d
PV
answer is A.
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Detailed Solution
∴ΔW=− Area of rectangle ABCD=-P2V=-2PVAccording to first law of thermodynamicsΔQ=Δu+ΔW or ΔQ=ΔW( As ΔU=0)i.e., heat supplied to the system is equal to the work doneSo heat absorbed, ΔQ=ΔW=−2PV∴ Heat rejected by the gas = 2PV