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In the figure, a cylinder A is initially rolling with velocity v on the horizontal surface of the wedge B (of same mass as A).All surfaces are smooth and B has no initial velocity. Then maximum height reached by cylinder on the wedge will be
detailed solution
Correct option is A
At the maximum height, vertical velocity of cylinder is zero. But horizontal velocity of the wedge and cylinder will be same.In the absence of friction between the cylinder and the wedge surface, angular velocity of cylinder remains constant. From energy conservation:12mv2+12Iω2=12mv′2+12Iω2+12mv′2+mgh.........(i)By the conservation of linear momentummv=2mv′ ⇒v′=v/2......(ii) From (i) and (ii): h=v2/4gTalk to our academic expert!
Similar Questions
In both the figures all other factors are same, except that in Figure (i) AB is rough and BC is smooth while in Figure (ii) AB is smooth and BC is rough. In Figure (i), if a sphere is released from rest it starts rolling. Now consider the Figure (ii), if same sphere is released from top of the inclined plane, what will be the kinetic energy of the sphere on reaching the bottom:
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