Questions
In both the figures all other factors are same, except that in Figure (i) AB is rough and BC is smooth while in Figure (ii) AB is smooth and BC is rough. In Figure (i), if a sphere is released from rest it starts rolling. Now consider the Figure (ii), if same sphere is released from top of the inclined plane, what will be the kinetic energy of the sphere on reaching the bottom:
detailed solution
Correct option is A
As we know that for pure rolling motion friction is necessary. So according to Fig (i) the sphere will roll from A to B then it will slip from B to C. In Fig(ii) the sphere slips from A to B and then it will roll from B to C.And we know then while rolling work done by friction force is zero hence kinetic energy after reaching bottom will be equal to mgh.Option (A) is correct choice.Talk to our academic expert!
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A sphere is rolling down an inclined plane without slipping. The ratio of rotational kinetic energy to total kinetic energy is
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