Questions
5 g of ice at 0°C is mixed with 5 g of steam at 100°C. What is the final temperature of the mixture?
a
200°C
b
400°C
c
300°C
d
100°C
detailed solution
Correct option is D
Heat required by ice to raise its temperature to 100°C is Q1=m1L1+m1c1Δθ1=5×80+5×1×100 = 400 + 500 = 900 calHeat given by steam, when condensed is Q2=m2L2=5×540=2700 calSince Q2>Q1, it means that the whole steam is not even condensed. Hence, temperature of mixture remains at 100°C.Talk to our academic expert!
Similar Questions
10 g of ice at 0°C is mixed with 100 g of water at 50°C. What is the resultant temperature of mixture?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
