A gas expands from volume V1 to volume V2 according to three different processes 1, 2 and 3. Change in internal energy of the gas in the processes are ΔU1,ΔU2 and ΔU3 respectively. If same quantity of heat is supplied in three cases, then
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a
ΔU1<ΔU2<ΔU3
b
ΔU1>ΔU2>ΔU3
c
ΔU2<ΔU3>ΔU1
d
ΔU1>ΔU3<ΔU2
answer is A.
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Detailed Solution
By first law of thermodynamics, ΔQ=ΔU+ΔW⇒ΔU=∆Q−ΔWNow ΔW1>ΔW2>ΔW3∴ ΔU1<ΔU2<ΔU3
A gas expands from volume V1 to volume V2 according to three different processes 1, 2 and 3. Change in internal energy of the gas in the processes are ΔU1,ΔU2 and ΔU3 respectively. If same quantity of heat is supplied in three cases, then