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Q.

A gas expands from volume V1 to volume V2 according to three different processes 1, 2 and 3. Change in internal energy of the gas in the processes are ΔU1,ΔU2 and ΔU3 respectively. If same quantity of heat is supplied in three cases, then

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a

ΔU1<ΔU2<ΔU3

b

ΔU1>ΔU2>ΔU3

c

ΔU2<ΔU3>ΔU1

d

ΔU1>ΔU3<ΔU2

answer is A.

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Detailed Solution

By first law of thermodynamics, ΔQ=ΔU+ΔW⇒ΔU=∆Q−ΔWNow ΔW1>ΔW2>ΔW3∴ ΔU1<ΔU2<ΔU3
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A gas expands from volume V1 to volume V2 according to three different processes 1, 2 and 3. Change in internal energy of the gas in the processes are ΔU1,ΔU2 and ΔU3 respectively. If same quantity of heat is supplied in three cases, then