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A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio CpCv of the mixture is

a
1.4
b
1.54
c
1.59
d
1.62

detailed solution

Correct option is D

For mixture of gases, Cv = n1Cv1+n2Cv2n1+n2where C = f2R, f is degree of freedomand Cp = n1Cp1+n2Cp2n1+n2where Cp = (1+f2)RFor helium, n1= 4, f = 3For oxygen, n2 = 12, f =5 ∴  CpCv = 4×5R2+12×7R24×3R2+12×5R2 = 4729    = 1.62

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