First slide

Law of equipartition of energy

Question

The average kinetic energy of a gas molecule at absolute temperature T is

Easy

A

directly proportional to T²
B

inversely proportional to T²
C

directly proportional to T
D

inversely proportional to T

Solution

We know that, kinetic energy, $KE = \frac{3}{2} k_{B} T$
where, $\frac{3}{2} k_{B}$ is constant, so $KE \propto T$
Now, we can say that the average kinetic energy of a gas molecule at absolute temperature T is directly proportional to T.

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