In a historical experiment to determine Planck’s constant, a metal surface was irradiated with light of different wavelengths. The emitted photoelectron energies were measured by applying a stopping potential. The relevant data for the wavelength ( λ ) of incident light and the corresponding stopping potential V0 are given below:Given that c=3×108ms−1 and e=1.6×10−19C , Planck's constant (in units of J s ) found from such an experiment is
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a
6.0×10−34
b
6.4×10−34
c
6.6×10−34
d
6.8×10−34
answer is B.
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Detailed Solution
From hv=W+KEmaxhcλ=W+V0e For λ=0.3μm:hc3×10−7=W+2×1.6×10−19→(1) For λ=0.4μm:hc4×10−7=W+1.6×10−19→(2)Subtract (1)−(2)⇒hc13−14×107=1.6×10−19 ⇒h=1.6×12×10−263×108=6.4×10−34Js