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Light of wavelength λph falls on a cathode plate inside a vacuum tube as shown in the figure. The work function of the cathode surface is ϕ and  the anode is a wire mesh of conducting material kept at a distance d from the cathode. A potential difference  V is maintained between the electrodes. If the minimum de Broglie wavelength of the electrons passing through the anode is  λe, Which of the following statement(s) is(are)true?

a
λe increases at the same rate as λph for  λph
b
λedecreases with increases in ϕand λph
c
λeis approximately halved, if   d  is doubled
d
For large potential difference  (v>>ϕ/e), λe is approximately halved if  V made four times

detailed solution

Correct option is D

K.E of electron just after ejection =hcλph-ϕK.E of electron when it reaches anode =Kmax=hcλph-ϕ+Ve   minimum de Broglie wavelength  λe=h2Kmaxmλe=h2hcλph-ϕ+Vem Given that Ve  >>ϕ   (hcλph is also small for visible light)∴λeα1V ⇒  when V is made 4 times, λe will be halved.

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Similar Questions

In a historical experiment to determine Planck’s constant, a metal surface was irradiated with light of different wavelengths. The emitted photoelectron energies were measured by applying a stopping potential. The relevant data for the wavelength ( λ ) of incident light and the corresponding stopping   potential  V0 are given below:

Given that c=3×108ms1 and e=1.6×1019C , Planck's constant (in units of J s ) found  from such an experiment is


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