Questions
An ideal gas is initially at temperature T and volume V. Its volume is increased by due to an increase in temperature pressure remaining constant. The quantity
detailed solution
Correct option is C
From ideal gas equation PV = RT ....(i)or PΔV=RΔT .. (ii) Dividing equation (ii) by (i) we getΔVV=ΔTT⇒ΔVVΔT=1T=δ Given∴ δ=1T So the graph between δ and T will be rectangular hyperbola.Talk to our academic expert!
Similar Questions
For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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