An ideal gas takes part in two thermodynamic processes ab and ac in which it is heated from the same initial state. The points b and c happen to be on an isotherm. In which process more heat is absorbed?
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a
in the process ab
b
in the process ac
c
in both the processes heat absorbed is same
d
we cannot decide with the data available from the diagram
answer is B.
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Detailed Solution
ΔQ = ΔW + ΔU. For both the processes ΔU is same as the points b, c are on isothermΔW in the process ab = (1/2)×(P+4P)×(2V-V) = 2.5PV.ΔW in the process ac = (1/2)×(P+2P)×(4V-V) = 4.5PV