If potential energy between a proton and an electron is given |U|=ke2/2R3, where e is the charge of electron and R is the radius of atom, then radius of Bohr's orbit is given by (h = Planck's constant , k = constant)
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a
ke2mh2
b
6π2n2ke2mh2
c
2πnke2mh2
d
4π2ke2mn2h2
answer is B.
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Detailed Solution
U=−ke22R3,F=−dUdR=−3ke22R4 But, F=mv2R⇒mv2R=3ke22R4 Also, mvR=nh2π Solve to get: R=6π2ke2mn2h2