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Q.

The kinetic energy of electron in the first Bohr orbit of the hydrogen atom is

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a

– 6.5 eV

b

– 27.2 eV

c

13.6 eV

d

– 13.6 eV

answer is C.

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Detailed Solution

K.E. = – (Total energy) = – (–13.6 eV) = + 13.6 eV
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