If the series limit of Lymen series for Hydrogen atom is equal to the series limit of Balmer series for a hydrogen like atom, then atomic number of this hydrogen-like atomwill be
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a
1
b
2
c
3
d
4
answer is B.
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Detailed Solution
By using 1λ=RZ21n12−1n22 For hydrogen atom, 1λminH=R112−1∞=R ⇒λminH=1R.......(i) For hydrogen like atom 1λminatom =RZ2122−1∞ ⇒ λminatom=4RZ2..........(ii) From equations (i) and (ii), 1R=4RZ2 ⇒Z=2