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lf the ratio of specific heat of a gas at constant pressure to that at constant volume is $γ$ , the change in internal energy of the mass of gas, when the volume changes from V to 2V at constant pressure p, is

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R(γ-1)

pV(γ-1)

γpV(γ-1)

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detailed solution

Correct option is C

∆U = nCv∆TAlso, CpCv = γ. Hence Cp-CvCv = γ-1This is Cv = R(γ-1). This gives ∆U = nRγ-1∆T = p∆Vγ-1= p(2V-V)γ-1 = pVγ-1

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lf the ratio of specific heat of a gas at constant pressure to that at constant volume is γ, the change in internal energy of the mass of gas, when the volume changes from V to 2V at constant pressure p, is

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lf the ratio of specific heat of a gas at constant pressure to that at constant volume is $γ$ , the change in internal energy of the mass of gas, when the volume changes from V to 2V at constant pressure p, is