First slide

laws

Question

A long narrow uniform glass tube is closed at one end and contains a gas trapped by a mercury thread of length h. When this tube is held vertical with open end up, the length of the gas column is L. When the tube is turned upside down, the length of the gas column is doubled. If the pressure of atmosphere is 75 cm of Hg, the value of h in cm is

Moderate

A

15
B

25
C

35
D

20

Solution

As there is no indication of change of temperature, Boyle’s law is assumed. $P_{1} V_{1} {= P}_{2} V_{2}$ . This gives $(75 + h) (LA) = (75 - h) (2 LA)$ . Solve for h

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