First slide

laws

Question

Two vessels separately contain two ideal gases A and B at the same temperature, the pressure of B being twice that of A. under such conditions. The density of A is found to be one-third of the density of B. the ratio of molecular weight of A and B is

Moderate

A

$\frac{1}{2}$
B

$\frac{2}{3}$
C

$\frac{3}{4}$
D

2

Solution

$\frac{P_{B}}{P_{A}} = \frac{V_{A}}{V_{B}}$
$V_{A} = 2 V_{B}$
$\frac{3 m_{A}}{V_{A}} = \frac{m_{B}}{V_{B}} m_{A} = \frac{2}{3} m_{B}$

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