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The magnetic flux linked with a coil at any instant ‘t’ is given by ϕ = 5t3 – 100t + 300, the e.m.f. induced in the coil at t = 2 second is

a
– 40 V
b
40 V
c
140 V
d
300 V

detailed solution

Correct option is B

e=−dϕdt=−ddt5t3−100t+300=−15t2−100 at t=2sec;e=40V

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