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To make the frequency double of a spring oscillator, we have to
detailed solution
Correct option is A
n∝km n2n1=m1m2 m1m2=n2n12=2n1n12=4 m2=m14Talk to our academic expert!
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An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is
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