Q.
An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is
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a
4 Mg/K
b
2 Mg/K
c
Mg/K
d
Mg/2K
answer is B.
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Detailed Solution
Let x be the maximum extension of the spring. From energy conservation Loss in gravitational potential energy = Gain in potential energy of spring Mgx=12Kx2⇒x=2MgK
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