An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is

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4 Mg/K

2 Mg/K

Mg/K

Mg/2K

answer is B.

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Detailed Solution

Let x be the maximum extension of the spring. From energy conservation Loss in gravitational potential energy = Gain in potential energy of spring Mgx=12Kx2⇒x=2MgK

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