The maximum acceleration of a particle in SHM is made four times keeping the maximum speed to be constant. It is possible when
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a
amplitude of oscillation is doubled while frequency remains constant
b
amplitude of oscillation is doubled while frequency is halved
c
amplitude of oscillation is made one-fourth while frequency is made four times
d
amplitude of oscillation remains constant while frequency is doubled
answer is C.
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Detailed Solution
amax=Aω2 ......(1)vmax=Aω ........(2)⇒amax=vmaxωSince, vmax is constant, to make amax four times, ω should be made four times.From (1), A should be made one-fourth.