A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is $$3.92$$×$$10$$−$$3m$$ . What must be the least period of these oscillations, so that the object is not detached from the platform

Question

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is $$3.92$$×$$10$$−$$3m$$ . What must be the least period of these oscillations, so that the object is not detached from the platform

Infinity Learn · Accepted Answer

By drawing free body diagram of object during the downward motion at extreme position, for equilibrium of mass mg−$$R=mA$$ $$(A$$ $$=$$ $$Acceleration)For$$ critical condition R $$=$$ $$0so$$ mg $$=$$ mA  ⇒$$mg=ma$$ω$$2$$⇒ω$$=g/a=9.83.92$$×$$10$$−$$3=50$$⇒$$T=2$$πω$$=2$$$$π$$$$50=0.1256sec$$

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is $3 .92 \times 10^{- 3} m$ . What must be the least period of these oscillations, so that the object is not detached from the platform

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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×10−3m . What must be the least period of these oscillations, so that the object is not detached from the platform

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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is $3 .92 \times 10^{- 3} m$ . What must be the least period of these oscillations, so that the object is not detached from the platform