The mean free path of nitrogen molecules at a pressure of 1 atm and temperature 0ºC is 0.8×10−7m. If the number density of molecules is 2.7×1025 per m3, then the molecular diameter is 3.2×N Ao. Find N.
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Detailed Solution
λ=12πnd2⇒d=12πλn=12π0.8×10-72.7×1025Substituting the values, we get,⇒d=0.32×10−9m=3.2Ao