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Q.

The mean free path of nitrogen molecules at a pressure of 1 atm and temperature 0ºC  is  0.8×10−7m. If the number density of molecules is  2.7×1025  per  m3, then the  molecular diameter is  3.2×N  Ao. Find N.

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Detailed Solution

λ=12πnd2⇒d=12πλn=12π0.8×10-72.7×1025Substituting the values, we get,⇒d=0.32×10−9m=3.2Ao
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