First slide

Law of conservation of momentum and it's applications

Question

N bullets each of mass m kg are fired with a velocity v ms^-1at the rate of n bullets per second, upon a wall. The reaction offered by the wall to the bullets is given by

Moderate

A

nmv
B

$\frac{Nmv}{n}$
C

$\frac{nNm}{v}$
D

$\frac{nNv}{m}$

Solution

The reaction force offered by the wall to the bullets = the force exerted by bullets on the wall (third law of motion) = the rate of change of momentum of bullets (second law of motion).
Now, total mass of N bullets = Nm.
Momentum of N bullets = Nmv.
Time $t = \frac{N}{n}$
So, the change of momentum per second = $\frac{Nmv}{\frac{N}{n}} = nmv$

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