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In the nuclear reaction given below
${}_{0}^{1}n +_{92}^{235} U \to_{Z}^{132} X +_{42}^{A} Y + 3_{0}^{1} n,$
Find the values of A and Z.

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detailed solution

Correct option is B

Equating mass numbers on both sides, 132+A+3=1+235⇒A=101Again, equating atomic number Z+42=92⇒Z=50

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In the nuclear reaction given belown 01+92235U→Z132X+42AY+301n,Find the values of A and Z.

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In the nuclear reaction given below
${}_{0}^{1}n +_{92}^{235} U \to_{Z}^{132} X +_{42}^{A} Y + 3_{0}^{1} n,$
Find the values of A and Z.