An electron is orbiting in 4^th energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to

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1.32 Å

13.2 Å

15.6 Å

20 Å

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detailed solution

Correct option is B

p=2mKE=2×9.1×10−31×0.85×1.6×10−19≈5×10−25 λ=hp=6.63×10−345×10−25≈13.2Å

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