Questions
An electron is orbiting in 4th energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to
a
1.32 Å
b
13.2 Å
c
15.6 Å
d
20 Å
detailed solution
Correct option is B
p=2mKE=2×9.1×10−31×0.85×1.6×10−19≈5×10−25 λ=hp=6.63×10−345×10−25≈13.2ÅTalk to our academic expert!
Similar Questions
Moving with the same velocity, which of the following has the longest de Broglie wavelength?
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