One mole of an ideal diatomic gas undergoes a transition from A to B along a path A B as shown in the figure,The change in internal energy of the gas during the transition is
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a
20 J
b
-12 kJ
c
20 kJ
d
- 20 kJ
answer is D.
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Detailed Solution
We know, ΔU=nCvΔT=n5R2TB-TA for diatomic gas, Cv=5R2=5nR2PBVBnR-PAVAnR [∵PV=nRT]=52PBVB-PAVA=522×103×6-5×103×4=52-8×103=-20 kJ