One mole of an ideal monoatomic gas is heated from state point A to state point C according to the process A-B-C as shown in figure. Then total heat supplied to the gas is
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a
3P0V0
b
52P0V0
c
32P0V0
d
4P0V0
answer is D.
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Detailed Solution
Process AB is a straight line and passes through the origin. So AB is isochoric process i.e. VB=V0∴ 2P0.V0TB=P0V0T0⇒TB=2T0∴ Q=QAB+QBC=n.CV.TB−TA+n.CP.TC−TB⇒Q=13R22T0−T0+15R23T0−2T0=4RT0=4P0V0