First slide

Heat given

Question

Carbon monoxide is carried around a closed cycle abc, in which bc is an isothermal process, as shown in the figure. The gas absorbs 7000 J of heat, as its temperature is increased from 300K to 1000K in going from a to b. The quantity of heat rejected by the gas during the process ca is

Moderate

A

4200 J
B

5000 J
C

9000 J
D

9800 J

Solution

From a to b heat absorbed = ${nc}_{v} dt$
$\frac{n 5 R}{2} (1000 - 300) = 7000$
$\frac{n 5 R}{2} \times (700) = 7000$
nR = 4
In the process c to a at constant pressure temperature decreases from 1000 to 300 K.
Heat rejected ${nc}_{p} dt$
$n \frac{7 R}{2} (700)$
$\frac{nR}{2} \times 7 \times 700$
$\frac{4}{2} \times 4900 = 9800 J$

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