One mole of a monoatomic gas is expanded isothermally from state A to state B. Then it is compressed isobarically from B to C and finally the gas returns to intial state A following isochoric process CA. Then heat rejected in the process BC is
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a
43P0V0
b
52P0V0
c
32P0V0
d
2P0V0
answer is B.
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Detailed Solution
Since AB is isothermal process, temperature of gas at state point B, TB=TANow 2P0.V0TA=P0V0TC⇒TC=TA/2∴ Heat rejected =n.CP.ΔT=1.(3+22)R.(TB−TC)=52R(TA2)=54(RTA)=54(2P0V0)=52P0V0
One mole of a monoatomic gas is expanded isothermally from state A to state B. Then it is compressed isobarically from B to C and finally the gas returns to intial state A following isochoric process CA. Then heat rejected in the process BC is