Download the app

Questions  

One mole of a monoatomic gas is expanded isothermally from state A to state B. Then it is compressed isobarically from B to C and finally the gas returns to intial state A following isochoric process CA. Then heat rejected in the process BC is 

a
43P0V0
b
52P0V0
c
32P0V0
d
2P0V0

detailed solution

Correct option is B

Since AB is isothermal process, temperature of gas at state point B, TB=TANow 2P0.V0TA=P0V0TC⇒TC=TA/2∴ Heat rejected =n.CP.ΔT=1.(3+22)R.(TB−TC)=52R(TA2)=54(RTA)=54(2P0V0)=52P0V0

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A thermodynamic system is taken through the cycle ABCD. as shown in figure. Total heat rejected by the gas during the cycle is


phone icon
whats app icon