Questions
A particle is projected with a speed at an angle above the horizontal surface such that the ratio of the kinetic energy at the highest point and the point of projection is 3:4. The change in velocity of the particle between these two points is
detailed solution
Correct option is A
The ratio of the kinetic energy at the highest point and point of projection is KHK0=34 ⇒1/2mv0cosθ21/2mv02=34 ⇒cos2θ=34⇒θ=π6 Change in velocity=v0sinθ/2=vo/2.Talk to our academic expert!
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