A particle is projected with a speed $v_o$ at an angle $\theta$ above the horizontal surface such that the ratio of the kinetic energy at the highest point and the point of projection is 3:4. The change in velocity of the particle between these two points is

• A

  $({\mathrm{v}}_{\mathrm{o}}/2)$vertically downward.

• B

  $({\mathrm{v}}_{\mathrm{o}}/2)$vertically upward.

• C

  $\sqrt{3}{\mathrm{v}}_0$due east.

• D

  $\left(\sqrt{3}{\mathrm{v}}_0/2\right)$vertically downward.