A ball is thrown with a velocity of u making an angle θ with the horizontal. Its velocity vector normal to initial vector (u) after a time interval of

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usinθg

ugcosθ

ugsinθ

ucosθg

answer is C.

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Detailed Solution

u→=(ucosθ)i^+(usinθ)j^ut=ucosθ i^+usinθ-gtj^ u→.ut→=0 u2cos2θ+usinθ(usin θ-gt) ⇒u2-usinθgt=0 t= ugsinθ

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