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In a photoelectric effect experiment a metallic surface having work function 2.2eV is illuminated with a light of wavelength  4000Ao.  An incident photon makes a collision with a free electron that lies well inside the target metal and the electron makes one collision before being ejected from the surface. If 10% of the energy of the electron is lost in the collision, The kinetic energy of the ejected electron is

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a

0.28ev

b

0.90ev

c

0.86ev

d

0.59ev

answer is D.

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Detailed Solution

Energy of photon =hcλ=124204000ev⇒hv=3.1evEnergy lost in the collision =10100 x 3.105 ev=0.31 evNow, hv=ϕ+k+Lost energy⇒ 3.1 = 2.2 + KE + 0.31 ⇒KE=0.59 ev
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In a photoelectric effect experiment a metallic surface having work function 2.2eV is illuminated with a light of wavelength  4000Ao.  An incident photon makes a collision with a free electron that lies well inside the target metal and the electron makes one collision before being ejected from the surface. If 10% of the energy of the electron is lost in the collision, The kinetic energy of the ejected electron is