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Light described at a place by equation E=200vmsin2×1015s1t+sin10×1015s1t   falls on metal surface having work function 2 eV, the maximum kinetic energy of photoelectrons?

a
8 eV
b
0 eV
c
4.59 eV
d
3.27 eV

detailed solution

Correct option is C

Larger frequency =v=10×10152π=5×1015πS−1 KEmax=hv−W0 ⇒4.14×10−155×1015π−2eV ⇒(6.59−2)eV=4.59eV

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