First slide

Graphs

Question

P–V diagram of an ideal gas is shown in the figure. Work done by the gas in the process ABCD is

Moderate

A

3P₀V₀
B

P₀V₀
C

4P₀V₀
D

2P₀V₀

Solution

$AB \to {w_1} = {P_0}({V_0} - 2{V_0}) = - {P_0}{V_0}$
$BC \to {w_2} = Pdv = 0\left( {\operatorname{since} \,v\,is\,\operatorname{constant} } \right)$
$CD \to {w_3} = 2{P_0}(3{V_0} - {V_0})$
$w = {w_1} + {w_2} + {w_3} = - {P_0}{V_0} + 0. + 4{P_0}{V_0} = 3{P_0}{V_0}$

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