Questions
A point source of light of power P and wavelength
detailed solution
Correct option is B
Intensity at a distance x from point source is given by I=P4πx2 consider an elemental shell of radius x and thickness dx, in this region, the energy contained is dE=Ic×4πx2dx=Pdxc Let dn be the number of photons in this elemental shell, then dn×hcλ=dE=Pdxc ⇒ dn=Pλdxhc2 Total no.of photons in the shell of inner radius r and outer radius 2r is n=∫dn=∫r2rPλdxhc2=Pλrhc2Talk to our academic expert!
Similar Questions
Two sources of light emit X – rays of wavelength 1nm and visible light of wavelength 500nm, respectively. Both the sources emit light of the same power 200W. The ratio of the number density of photons of X – rays to the number density of photons of the visible light of the given wavelength is :
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests